peter and jane have $90 together if peter gave jane $16 he would have $14less than jane how much does peter originally have

peter = $54

jane = $36

Step-by-step explanation:

let peter = x

let jane = y

peter + jane = $90

x+y = 90 (1)

peter gave jane $16 = x-16

jane gets extra $16 from peter = y+16

peter would have $14 less than jane

jane - peter = $14

(y+16)-(x-16) = 14

y+16-x+16 = 14

y-x+32 = 14

y-x = 14-32

y-x = -18 (2)

x+y = 90 (1)

y-x = -18 (2)

from (1)

x+y = 90

y = 90-x (3)

substitute (3) into (2)

y-x = -18

90-x-x = -18

90-2x = -18

-2x = -18-90

-2x = -108

x = 54

substitute x = 54 into (3)

y = 90-x

y = 90-54

y = 36

x = peter = $54

y = jane = $36

i'm pretty sure it's c. nvm

true !

step-by-step explanation: