What is the equation of a line, in point-slope form, that passes through (-8, 1)and has a slope of ? O y+1=(x - 8)
Oy+8= 5 (1-1)
oy-1-5(x + 8)
Oy-8= + (x+1)

y-1 = 5(x+8)

Step-by-step explanation:

The standard equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

m is the slope

(x0, y0) is the point

Given

Slope m = 5 (assumed value)

Point (-8,1)

Substitute the given data's into the formula

y -1 = 5(x-(-8))

y-1 = 5(x+8)

Hence the required equation is y-1 = 5(x+8)

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