the length of each side of a square increases by 40%. by what percent does the area of the square increase?

96%

Step-by-step explanation:

If you substitue values for the sides of the square, you can easily solve this problem.

If the side of each square was 10, then the area of the square would be 100. A 40% increase in side length would mean 10×.4 = 4 --> 10+4= 14.

14 would be your new side length meaning that the area would be 196.

From this, you can see that there is an increase by 96 from the original to the 40% increase. Since the value was initially 10, we can turn the 96 increase into 96 percent.

40% iincrease

Step-by-step explanation:

A=l^2  (area of a square)      let the unknown dimensions be x                                                                                                                   Area of the original square without change=(x^2)                                                          Area of the square undergoing change =(1.4x^2)                                                            thus,% change=new-old/old*100%                                                                                   1.4-1.0=0.4*100=40%                                                                                    

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer