At a regional soccer tournament, tickets for two adults and seven students cost $60. Tickets for three adults and eleven students cost $93. Determine the price of an adult ticket and the price of a student ticket. The price of an adult ticket is $, and the price of a student ticket is $

The price of an adult ticket is $9 and the price of a student ticket is $6

Step-by-step explanation:

Create a system of equations where x is the price of an adult ticket and y is the price of a student ticket:

2x + 7y = 60

3x + 11y = 93

Solve by elimination by multiplying the top equation by 3 and the bottom equation by -2, to cancel out the x terms:

6x + 21y = 180

-6x - 22y = -186

Add them together:

-y = -6

y = 6

Then, plug in 6 as y into one of the equations to solve for x:

2x + 7y = 60

2x + 7(6) = 60

2x + 42 = 60

2x = 18

x = 9

So, the price of an adult ticket is $9 and the price of a student ticket is $6

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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