A 2-Newton upward net force is being applied to a 10-kg object. What is the magnitude of the upward acceleration on the object (in m/s2)

The magnitude of the upward acceleration on the object is 0.2 m/s²

Step-by-step explanation:

The given parameters are;

The net upward force applied to the object, F = 2 Newtons

The mass of the object, m = 10-kg

According to Newton's second law of motion, Force, F, is directly proportional to acceleration, a, of the object to which the force is applied, and the direction of the acceleration is in the direction of the applied force, therefore, we have;

Force, F = Mass, m × Acceleration, a

From which we have;

Acceleration, a = F/m which gives;

a = 2-N /10-kg = 0.2 m/s²

The magnitude of the upward acceleration on the object, a = 0.2 m/s².

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?