Calculate the Compound interest for 18,000 for 2 years at 8% per annum compounded annually.

AGAIN URGENT
THANK U

Step-by-step explanation:

principal = 18000

Time = 3 yrs

Rate. = 8%.

CI. = ?

Now

CI = p ( 1+ R÷ 100) ^T

CI = 18000( 1+ 8÷ 100 ) ^ 2

CI = 20995.2

Hope it's is Right :-)

interest ( I ) , principal ( P ), Time ( T ) , Rate ( R )

P = I×T×R

100

P = 18,000×2×8

100

= 18,000×16

100

so two zero cancel other two zero living

= 180×16 = 180 × 16

1

= 180 × 16

P = 2880

1

we fixe in the values

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

if you need , reply with more info. u.