For a study of adolescents' disclosure of their dating and romantic relationships, a sample of 224 high school students was surveyed. One of the variables of interest was the level of disclosure to an adolescent's mother (measured on a 5-point scale, where 1 = "never tell" and 5 ="always tell"). The sampled high school students had a mean disclosure score of 3.38 and a standard deviation of 0.98. The researchers hypothesize that the true mean disclosure score of all adolescents will exceed 3. Do you believe the researchers? Conduct a formal test of hypothesis using α = 0.05. Set

 The  decision rule is  

Reject the null hypothesis

   The conclusion is

There sufficient evidence that the true mean disclosure score of all adolescents will exceed 3

Step-by-step explanation:

From the question we are told that  

      The sample is  n  =  224

      The  sample mean is

      The standard deviation is  

      The population mean is

       The level of significance  is  

The null hypothesis is  

The alternative hypothesis is  

Generally the test statistics is mathematically represented as

=>      

=>      

From the z table  the area under the normal curve to the right corresponding to 5.80  is

From the value obtained we that , hence  

   The  decision rule is  

Reject the null hypothesis

   The conclusion is

There sufficient evidence that the true mean disclosure score of all adolescents will exceed 3

answer: idk

step-by-step explanation:

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.