Hi! please help me the blue line is what I have to find.

Pretie sure answer is 0

Step-by-step explanation:

first you take the 1 and subtract it from -3

which is -2 then add the other 2 to the -2 which is 0

then you devide 5 with 5 and 5 with zero which leaves you with zero and 0=x

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

5/12, or 5: 12

step-by-step explanation: