HELP! PLZ Let $x^2+bx+c = 0$ be a quadratic whose roots are each two more than the roots of $3x^2-5x-7$. What is $c$?

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  c = 5

Step-by-step explanation:

The graph of

  f(x) = 3x² -5x -7

is shifted 2 units to the right by the transformation ...

  g(x) = f(x -2)

  g(x) = 3(x -2)² -5(x -2) -7

  g(x) = 3(x² -4x +4) -5x +10 -7

  g(x) = 3x² -17x +15

When this is written as a monic polynomial, it is

  g(x) = x² -17/3x +5

The value of 'c' is 5.

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.