A Parking lot holds 42 cars. There are 26 cars in the lot already. Which inequality can be solved to show all the number of cars c that can still park in the lot? 1. 26 + c _< 42 2. 26 + c > 42 3 26 + c _> 42 4. 26 + c < 42

A).  26 + c ≤ 42

Since there are only 42 spots available, 42 must be greater or equal to the number of cars parked. 26 represents the number of cars already parked, and c represents the number of spots left over. From this information, we can use the equation 26 + c ≤ 42 to represent the scenario.

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4