Suppose that 2% of produced computers by a company have defects, and defects occur independently of each other. a) Find the probability of exactly 2 defective computers in a shipment of 100 computers. b) The probability that a computer support specialist needs to test at least N computers in order to find one defective computer is 0.6676. Find N.

a)  P(exactly two defectives) = 0.2734

b) N 55

Step-by-step explanation:

From the given information:

P(exactly two defectives) = P(X =2) =

= 0.2734

Thus, P(exactly two defectives) = 0.2734

b)

To find:

P(X ≥ 1 )

let X be the random variable that obeys a binomial distribution, X represents the number of defectives,

∴

N log (0.98) = log (0.3324)

N = 54.51824841

N 55

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it