Mr. Logan spent 14 cents at the hardware store buying nails and screws. Nails cost 2 cents, and screws cost 1 cent. If Mr. Logan bought exactly 9 items, how many of each did he buy? Please help me fast !!!

5 nails and 4 screws

Step-by-step explanation:

Make it into an expression where N= amount of nails bought and S= amount of screws bought. Then set it equal to the amount he paid.

ie: 2n+1s=14

Now make another equation for how many he bought.\

ie: n+s=9

Now subtract one of the letter variables from the second equation to get one on alone.

ie: n=9-s

Now, since you have a value for N, substitute it for the value in the original equation so that there's only one variable.

ie: 2(9-s)+1s=14

Now solve for S.

ie: 18-2s+s=14

ie: -s=-4

ie: s=4

Now you have a number value for S that you can plug in the original equation to find the value of N.

ie: 2n+4=14

ie: 2n=10

ie: n=5

Now plug in your values for N and S into the original equation to check it. Your answer is 5 nails and 4 screws.