Suppose that scores on a particular test are normally distributed with a mean of 140 and a standard deviation of 18. What is the minimum score needed to be in the top 5% of the scores on the test? Carry your intermediate computations to at least four decimal places, and round your answer to one decimal place.

153.16

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = ???

μ is the population mean = 140

σ is the population standard deviation = 8

Top 5% means the score is in the 95th percentile

The z score of 95th percentile = 1.645

1.645 = x - 140/8

Cross Multiply

1.645 × 8 = x - 140

13.16 = x - 140

x = 13.16 + 140

x = 153.16

Therefore, the minimum score needed to be in the top 5% of the scores on the test is 153.16

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

answer: add the !

step-by-step explanation: then we will answer