9hr. 8min+ 6hr. 42min.+ 8hr. 39min.

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Explain step-by-step how to simplify -5(2x – 3y + 6z – 10).

In the diagram, gef and hef are congruent. what is the value of x