A ball is dropped from a height of 50 feet. The function f(x) = 50(0.6)x gives the height in feet of feet of each bounce, where x is the bounce number. What is the height of the third bounce to the nearest tenth of a foot?

The height of the third bounce is 10.8 feet

Step-by-step explanation:

Let us solve the question

∵ A ball is dropped from a height of 50 feet

∵ The function f(x) = 50 gives the height in feet of each bounce

∵ x is the bounce number

∵ We need to find the height of the third bounce

∴ x = 3

→ Substitute x by 3 in the function above

∵ f(3) = 50(0.6)³

∴ f(3) = 50(0.126)

∴ f(3) = 10.8

∴ The height of the third bounce is 10.8 feet

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841