A bird traveled a horizontal distance of 300ft over a distance that rose 150ft what is the angle of elevation that the bird made with the ground . Round to the nearest tenth

26.56 degrees

Step-by-step explanation:

The set up will give a right angles triangle

Given

The Horizontal distance = Adjacent side = 300ft

The height = Opposite side = 150ft

Using the SOH CAH TOA identity;

tan theta = opposite/adjacent

tan theta = 150/300

tan theta = 1/2

theta = arctan 1/2

theta = 26.56 degrees

Hence the angle of elevation is 26.56 degrees

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

step-by-step explanation: