Afootball quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. he misses the receiver on the first throw 30% of the time. when his first throw is incomplete, he misses the receiver on the second throw 10% of the time. what is the probability of not throwing the ball to a receiver on either throw?

The chance of not throwing the ball to a receiver on either throw is 0.0375, or 3.75 percent.

Step-by-step explanation:

This is event A when he misses the first throw. P(A) = 25%, or 0.25

Because event B takes place only after event A.

When he misses on the second throw, event B occurs. P(B/A) = 15% or 0.15

P(ANB) = P(A) P(B/A) P(ANB) = (0.25)x(0.15) P(ANB) = 0.0375 is the probability of both events occurring.

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4