Find three consecutive even integers such that the sum of the second and third is 3 times the first integer.

, and

Step-by-step explanation:

Let smallest consecutive even integer.

Since the second and third consecutive even integers can be expressed by our smallest even consecutive integer, we can express them as:

Second consecutive even integer =

Third consecutive even integer =

From "the sum of the second and third is 3 times the first integer", we can write:

(collect like-terms)

∴ The first consecutive even integer is 6

Now, we can use substitution to find the values of the second and third consecutive even integers:

Second consecutive integer =

Third consecutive integer =

∴ The three consecutive even integers are , and .

Hope this helps :)

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)