What is an equation in slope-intercept form of the line that passes through (6, −7) and is perpendicular to the line shown below?

A.

Step-by-step explanation:

Equation of a Line

The equation of the line in slope-intercept form is:

y=mx+b

Where:

m = slope

b  = y-intercept.

The point-slope form of the equation of a line is:

y - k = m ( x - h )

Where:

(h,k) is a point through which the line passes.

The line we are looking for has a slope defined for the fact that is perpendicular to the line shown in the graph.

Two perpendicular lines with slopes m1 and m2 satisfy the equation:

We'll find the slope m1 of the given line and then solve the above equation for m2:

The line of the graph passes through two clear points (-3,-3) and (0,3). Let's calculate the slope.

Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

Now we calculate the second slope:

We use the point-slope form, given the point (6,-7):

Operating the parentheses:

Simplifying:

A.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

{3 + i, 3 - i, 3, -1}

step-by-step explanation: