Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE =2x, BE = y +10, CE =x+2 and DE = 4y - 8. Find x.
A. 4
B. 6
C. 2
D. 8

Step-by-step explanation:

Given parallelogram ABCD with diagonals AC and BD intersect at point E, then;

AE = CE and BE = DE

Given;

AE =2x, BE = y +10, CE =x+2 and  DE = 4y - 8.

Recall that AE = CE

2x = x+2

2x - x = 2

x = 2

Hence the value of x is 2

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47