B) The sum of the ages of the father and son is 44 years. After 8 years, the age of father will be twice the age of the son. Find their present ages,

Let the present age of father = x years

and the present age of son = y years

according to the first condition

x + y =44 (i)

according to the second condition

x+8 = 2(y+8)

or x+ 8 = 2y + 16

or x- 2y = 8 (ii)

solve the equation (i) & (ii) we get

x + y =44

x- 2y = 8

••••••••••••••••••••••••

3y = 36

or y = 12

put the value of y in equation (i), we get

x + 12 =44

or x = 32

so the present age of father = x =32 years

and the present age of son = y = 12 years.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

18.75 gallons

step-by-step explanation: