A designer places four identical tiles on a surface and spaces them 3 5/16 inches apart. Each tile is 7 1/4 inches wide. What is the length from the outside edge of the first tile to the outside edge of the last tile?

40¹/₂ inches

Step-by-step explanation:

Since there are 4 tiles, there will be 3 spaces between them. So the length covered by the spaces L = length of one space × number of spaces = 3⁵/₆ × 3 = 23/6 × 3 = 23/2 = 11¹/₂ inches.

The total length covered by the 4 tiles is L' = length of one tile × number of tiles = 7¹/₄ × 4 = 29/4 × 4 = 29 inches.

So, the total length covered by the 4 tiles and 3 spaces between is L'' = 29 inches + 11¹/₂ inches = 41¹/₂ inches which is the length from the outside edge of the first tile to the outside edge of the last tile.

So, the length from the outside edge of the first tile to the outside edge of the last tile is the length from the outside edge of the first tile to the outside edge of the last tile 40¹/₂ inches

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7