Gary made a scale drawing of his game room. The scale drawing has a length of 3 inches and a width of 5 inches. If the game room has an actual length of 12 feet, which equation could be used to determine w, the width of the game room?

Given :

Gary made a scale drawing of his game room.

The scale drawing has a length of 3 inches and a width of 5 inches.

To Find :

If the game room has an actual length of 12 feet, which equation could be used to determine w, the width of the game room.

Solution :

We know, during making scale drawing of any thing the shape of the object is same as the real one i.e. the ratio of each dimension remains constant.

Let, width of the gaming room is w.

Therefore, the width of the game room is 20 inches.

answer: entity is prob the answer

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct