A bridge hand is made up of 13 cards from a deck of 52. Find the probability that a hand chosen at random contains at least .

10%

Step-by-step explanation:

Since the question is not complete, I will be solving for probability of 3 9s

To solve this, we would be using the principle of combination, and thus

A deck of 52 hours has 4 nines, the probability that it contains at least 3 9s is mathematically represented by the equation.

P ( x ≥ 3 ) = ( 48 C 10 · 4 C 3 ) / ( 52 C 13 ) + ( 48 C 9 · 4 C 4 ) / ( 52 C 13 )

Remember I told us were going to be using the principle of combination. Well then

nCr = n!/r!(n - r)!

Now, applying the above stated formula to the equation, we have

48C10 = 48!/10!(38!)

4C3 = 4!/3!(1!)

52C13 = 52!/13!(39!)

48C9 = 48!/9!(39!)

4C4 = 4!/4!(0!)

Solving for each independently, we find that

= 0.0412 + 0.588 = 0.1

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step-by-step explanation:

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