*The sum of 5% of one number and 4% of a second number is 44. The sum of 4% of the first number and 5% of the second number is 46. Find the numbers.

The first number be x is 400 and the second number be y is 600.

Given that,

The sum of 5% of one number and 4% of a second number is 44.

The sum of 4% of the first number and 5% of the second number is 46.

We have to find,

The numbers.

According to the question,

Let, the first number be x,

And the second number be y,

Then,

5% of x = 0.05x

4% of y = 0.04y

The sum of 5% of one number and 4% of a second number is 44 then, the equation is,

0.05x + 0.04y = 44

And As the sum of 4% of one number and 5% of a second number is 46 then, the equation becomes,

5% of y = 0.05y

4% of x = 0.04x

0.04x + 0.05y = 46

On solving both the equations multiply both the equation by 100,

From equation 1,

Substitute the value of x in equation 2,

Substitute the value of x in equation 1,

Hence, The first number be x is 400 and the second number be y is 600.

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The numbers are:

Step-by-step explanation:

Let 'x' be the first number

Let 'y' be the first number

5% of x = 5/100x = 0.05x

4% of y = 4/100y = 0.04y

so the equation becomes

0.05x + 0.04y = 44

Also

4% of x = 4/100x = 0.04x

5% of y = 5/100y = 0.05y

so the equation becomes

0.04x + 0.05y = 46

Thus, the system of the equations becomes

0.05x + 0.04y = 44

0.04x + 0.05y = 46

solving the system of the equation

isolate x for 0.05x + 0.04y = 44

Multiply both sides by 100

Divide both sides by 5

simplify

now isolate y for

Divide both sides by 18

Therefore, the numbers are:

4.08%

step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.