An architect is trying different dimensions for the room shown below. Write an algebraic expression the architect can use to find the area of the room then find the area when x is 6 m. Show your work.

x² + 12

48m²

Step-by-step explanation:

Find the diagram attached.

The room can be segregated into two rectangles

The area of the room = Area of bottom rectangle + area of the top rectangle

Area of the bottom rectangle = x * (x-3) = x² - 3x

Area of the top rectangle = 3* (4+x) = 12 + 3x

The area of the room = x² - 3x + 12 + 3x

Area of the room = x² + 12

Hence the algebraic expression that the architect can use to find the area of the room is x² + 12

Given x = 6m

The area of the room = x² + 12

The area of the room = 6² + 12

The area of the room = 36 + 12

The area of the room = 48m²

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

only 10/60 isn't equivalent

hope this : )