in an examination ,80%examines passed in English ,70%in mathematics and 60% in both subject if 45 examines failed in both find the number of examines who passed only one subject also the number of examines who failed mathematics

135 and 135

Step-by-step explanation:

The computation is shown below:

The number of examiners who passed in only one subject is as follows

=  n(E) - n(E ∩M) + n(M) - n(E ∩M)

= (80 - 60 + 70 - 60)%

= 30%

Now the number of students who passed in minimum one subject is

n(E∪M) = n(E) + n(M) -  n(E ∩M)

= 80 - + 70 - 60

= 90%

Now the number of students who failed in both subjects is

= 100 - 90%

= 10% of total students

= 45

So total number of students appeared for this 450

So, those who passed only one subject is

= 450 × 30%

= 135

Now the Number of students who failed in mathematics is

= 100% - Passed in Mathematics

= 100% - 70%

= 30% of 450

= 135

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^