What is the result when x^3-8x^2+19x-14x 3 −8x 2 +19x−14 is divided by x-2x−2? If there is a remainder, express the result in the form q(x)+\frac{r(x)}{b(x)}q(x)+ b(x) r(x) .

The result when x^3-8x^2+19x-14 is divided by x^2-2x−2 is

.

Step-by-step explanation:

Seems the divisor in the question is x^2-2x−2. If so, the solution to the division is shown using the long division method in the attachment below.

The result is

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16