Write a polynomial function of least degree with integral coefficients that has the given zeros. 2, -1, 3 NEED EXAMPLES ON HOW TO GET THE PROBLEM USIN FOIL METHOD.

Step-by-step explanation:

*Assuming you meant polynomial function of degree 3*

The given zeros are 2, -1, and 3. To get the zeros in the first place, we have a deconstructed polynomial that looks like this:

(x-2)(x+1)(x-3)

Now, we can foil these out. **Quick note: if the degree of your polynomial is greater than 3, simply put a square root on one of the terms: (x-2)^2

After foiling you should get: x^3-4x^2+x+6

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

x = 23.78

step-by-step explanation: