A constant force of 15 N is being applied at a constant angle os 30 degree on an object at the same time that a constant force of 25 N at a constant angle of 60degree is acting on the object. What is the magnitude and direction of the resultant force?

Step-by-step explanation:

Solution:

(a) is the vertical direction, the force of gravity

on the object (or the wight force: w = Mg ) pulls the crate down while the surface reaction. N. pushes it 103N

rd, as shown:

w = Mg = (20.0kg 9.8m s3 - 196N

N- 196N as well

(b) In the horizontal direction, in the absence of

friction, there are two forces: (F) and the 53-N force. Applying the Newton's 2nd law helps the calculation of the unknown force. F. F - 53N (20.0 kg)(2.5 m 3

F = 103N plz mark me as brainliest

(-5,-28)

i graphed to on desmos.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.