What values for PQ and RL make the following equation true px to the power of rtwo+wx+r equals(3x+1)(3x+2)HURRY

P= 3

Q= -14

R= -5

Step-by-step explanation:

Just solve the equation on the right side, you'll get:

=3x^2 -15x +x -5

=3x^2 -14x -5

Now compare it to the equation on the left side,

The coefficient of x^2 on the left is "p", on the right that we just solved is 3.

Same for "q" which is the coefficient on the left, on the right it's -14.

And for "r" it's -5 from the equation on the right.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

a reflection across the x axis and a 90 degree rotation left and right.