A bowling alley charges $2.50 per game plus $4 to rent shoes. A second bowling alley charges $4 per game plus $1 to rent shoes. How many games would a person have to play for the two bowling alleys to cost the same amount?

The person would have to play 2 games for the two bowling alleys to cost the same amount

Step-by-step explanation:

Assume that the number of games that makes the two costs equal is x

∵ A bowling alley charges $2.50 per game plus $4 to rent shoes

∵ The number of games is x

∴ The cost = 2.50x + 4

∵ A second bowling alley charges $4 per game plus $1 to rent shoes

∵ The number of games is x

∴ The cost = 4x + 1

∵ They have the same cost

→ Equate the 2 expressions above

∴ 4x + 1 = 2.50x + 4

→ Subtract 2.50x from both sides

∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4

∴ 1.50x + 1 = 4

→ Subtract 1 from both sides

∵ 1.50x + 1 - 1 = 4 - 1

∴ 1.50x = 3

→ Divide both sides by 1.50

∴ x = 2

∴ The person would have to play 2 games for the two bowling alleys to

   cost the same amount

step-by-step explanation:

for volume, add base x height x width

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube