Write an equation of the line that passes through (2,0) and is perpendicular to the line y=-1/7x-3 An equation of the perpendicular line is y=

Step-by-step explanation:

The slope of the given line y=-1/7x-3 is -1/7.  The slope of any 'new' line perpendicular to this given line is the negative reciprocal of the slope of the latter, which in this case is +7.

Use the point-slope formula y - k = m(x - h) with k = 0, h = 2 and m = +7:

y - 0 = 7(x - 2), or

y = 7(x - 2), or

y = 7x - 14

the answer will be

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

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