A number cube with faces numbered 1
to
6
is rolled
15
times. In theory, how many times would you expect to roll a number greater than
2
?

10

Step-by-step explanation:

You could roll a 1,2,3,4,5,6  or have 6 possibilities

There are 4 of them greater than 2 ( 3,4,5,6)

P( greater than 2 ) = possibilities greater than 2 / total = 4/6 = 2/3

Multiply this by the number of rolls

15 * 2/3 = 10

I would expect 10 rolls to have a number greater than 2

the best estimate is 3 because   8 can only go into 24 3 times