A toy army man with a parachute is dropped and follows the path f(x)=−12(x−1)2+8. At the same time someone throws a paper airplane that flies on a path modeled by the equation g(x)=−x+9. a. After how many seconds will the army man and the paper airplane first collide? b. What height are the objects at when they collide?

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: