A function has a y-intercept of 4 and two x-intercepts, one at 3 and one at 6. Which could be this function?
O
y = 3x2 + 6x + 4
O y = 6x2 + 3x +4
Oy
y= 22 - 6x - 4
O y= 22 - 2x + 4

D) y=2/9x2+2x+4

Step-by-step explanation:

y-intercept=4

2 x intercepts= 3 and 6

so y-intercept is point where x is 0 like (0,y)

x-intercept is the opposite y is 0 (x,0)

that means y-intercept is (0,4)

x-intercept is (3,0) and (6,0)

the formula of slope intercept form is

y=mx+b

b= is y-intercept

that means

y=ox^2+mx+4

x-intercept is point where y is 0

so solve

now lets try the first option

This is are quadratic functions

you need to plug in both of these until u get one that is right

change the y until you get both x's

the first option if wrong

second one  y = 6x2 + 3x +4 has no x-intercepts

3rd option y=3/4x^2-6x-4

last option is y=

2/

9

x2+2 has points at -6. and -2.9999 or -3

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

the answer is 1/4

step-by-step explanation: