Mathematics, 18.12.2020 01:10, kamayabrown668
25 POINTS FOR WHOEVER ANSWERS THIS QUESTION PLEASE HELP!
An inverted conical tank with a height of 10 ft and a radius of 5 ft is drained through a hole in the vertex at a rate of 5 ft^3/s. What is the rate of change when the water depth is at 4 ft?
a.) Let V be the volume of water in the tank and let h be the depth of the water. Write an equation that relates V and h.
b.)Differentiate both sides of the equation with respect to t. dV/dt = () dh/dt
c.) when the water depth is 4 ft, the rate of change of the water depth is about . (Round to nearest hundredth if needed.)
Answers: 2
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