Which ordered pairs are in the solution set of the system of linear inequalities? y>-1/3x+2
y<2x+3

A. (2, 2), (3, 1), (4,2)
B. (2, 2), (3,-1), (4, 1)
C. (2, 2), (1, -2), (0, 2)
D. (2, 2), (1, 2), (2, 0)

i can answer this question sweetie!

step-by-step explanation:

hello! just here for points! though i wish i knew!

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

the formula of a midpoint between a abd b: