There are 25 students in the class. Is it possible that 6 of them have 9 friends each, 8 of them have 8 friends each, and 11 of them have 7 friends each

It is not possible

Step-by-step explanation:

First 6 people have 9 friends and since 6 people can have totally the same friends which could all be each other, we would have 5 friends(from same 6 people) + 4 friends(not from the 6). Therefore we would have total 9 people/students

In second group of 8 people, their friends could entirely be the same be the same as the first group's friends or they could all be each other's friend hence just an additional 8 students to the population

In the third group of 11 people/students, same thing could apply as above but total number of students would always surpass 25 with the additional population. Example 9+8+11= 28

Therefore it is not possible that 25 students would each have those number of friends.

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.