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Mathematics, 17.12.2020 20:50, russboys3
SoIve each equation. TWO of these are special cases ("no solution" and " all real numbers ".)
4 (j-7) =12
7(2p +3 - 8 =6p +29
2 ( x-1) = 4+2x
3(4c+5)=27
4(2k-6) +11 =8k -13
![answer](/tpl/images/cats/otvet.png)
Answers: 3
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SoIve each equation. TWO of these are special cases ("no solution" and " all real numbers ".)
4 (j-...
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