I WILL GIVE BRAINLIEST Aisha owns an apparel store. She bought some shirts and jeans from a wholesaler for $3,900. Each shirt cost $12 and each pair of jeans cost $28. If she sold the shirts at 70% profit and jeans at 125% profit, her total profit was $3,885. How many shirts and jeans did she buy from the wholesalers? 101 shirts and 96 jeans
129 shirts and 84 jeans
150 shirts and 75 jeans
160 shirts and 71 jeans

Let the number of shirts be x, and the jeans be y.

Total cost of shirts = 12x

Total cost of Jeans = 28y

This means that:        12x + 28y = 3900(a)

Selling price for Shirts 70% profit, means = 100% + 70% = 170% of the cost price

170/100  * 12x = 1.7*12x = 20.4x  

Selling price for Jeans 125% profit, means = 100% + 125% = 225% of the cost price

225/100  * 28y = 2.25*28y = 63y

Total profit = 3885, remember total cost = 3900

Total selling price = 3885 + 3900 = 7785

20.4x + 63y = 7785(b)

12x + 28y = 3900(a)

20.4x + 63y = 7785(b)

Solving the simultaneous equation with a programmable calculator:

x = 150, y = 75

150 shirts and 75 jeans.

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150 shirts and 75 jeans

Step-by-step explanation:

s = shirts

j = jeans

12s+28j = 3900

The profit on the shirts is 70 percent so we multiply 12 by .7  

12*.7 = 8.4

The profit on the jeans is 125 percent so we multiply 28 by 1.25  

The profit was 3885

28*1.25 = 35

8.4s+ 35j=3885

We now have 2 equations and 2 unknowns

12s+28j = 3900

8.4*s+ 35j=3885

I am going to solve by elimination

Multiply the first equation by -.7

-.7 (12s+28j )= -.7*3900

-8.4s -19.6j=-2730

Add this to the second equation

-8.4s -19.6=-2730

8.4s+ 35j=3885

15.4j = 1155

Divide each side by 15.4

15.4j/15.4= 1155/15.4

j = 75

Now we need to find the shirts.

We will substitute j=75

12s+28(75) = 3900

12s +2100 = 3900

Subtract 2100 from each side

12s = 3900-2100

12s = 1800

Divide by 12

12s/12 = 1800/12

s =150

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step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.