Which ordered pairs represent the following transformation? translation: 3 units right and 4 units up
Z(-4,-3), 1(-2,-2), V(-2,-4)
Z'(1,1), l'(1,5), V'(1,0)
O Z'(-1,1), l'(1,2), V'(1,0)
Z'(-1,-1), I'(4,2), V (1,0)
O Z'(-7,0), l'(6,7), V'(0,0)

I’ll GIVE BRAINLIEST

the barter

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)