The weight, X, of cherry tomatoes selected at random from a very large bin at the local supermarket follows a Normal distribution with mean 3 oz. and standard deviation 2 oz. Suppose we pick 8 cherry tomatoes from the bin at random (independently) and put them in our bag. What is the probability that exactly 5 of the 8 cherry tomatoes weigh less than 4 oz (rounded to the nearest 0.01)?

the probability that exactly 5 of the 8 cherry tomatoes weigh less than 4 oz is 0.05

Step-by-step explanation:

Given that;

X has normal distribution has mean µ = 3

standard deviation σ = 2  

now

P( x< 4) = P( (x-µ)/σ /(3-4)/5)

= P( z < -0.5 )

= 0.3085  {from the z-table}

X has binomial distribution with n = 8 and p = 0.3085

so P(x=5)

P(x=5) = 8C₅(0.3085)⁵ (1 - 0.3085)⁸⁻⁵

= 0.0517  ≈ 0.05

Therefore the probability that exactly 5 of the 8 cherry tomatoes weigh less than 4 oz is 0.05

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph