A survey showed that 70% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 7 adults are randomly selected, find the probability that exactly 2 of them need correction for their eyesight.

0.0250047

Step-by-step explanation:

Given that :

Proportion who need correction glasses = 70%

Number of trials = 7

Probability that exactly 2 needs correction glasses :

Using a binomial probability formula :

P(success) = p = proportion who need glasses = 0.7

P(x =x) = nCr * p^x * (1 - p)^(n - x)

P(x = 2) = 7C2 * 0.7^2 * 0.3^(7 - 2)

P(x = 2) = 7C2 * 0.7^2 * 0.3^5

P(x = 2) = 21 * 0.49 * 0.00243

P(x = 2) = 0.0250047

i think asking google will you get the answer to that question

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3