What is the relationship among mL BCD, M L A, and m L B in the figure below?
B
75
40°
A.
40 ° + 75° = 180° - m 2 BCD
В.
40° + 75° = m 2 BCD
C 40° - 75º = m 2 BCD
D
40° - 75°+ m BCD = 180°
hans did not square the 40-unit side; he merely multiplied it by 2. incorrect.
answered: Guest
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