Which equation could possible represent the graphed function? a. f(x)= (x-1)(x+2)(x+3)
b. f(x)= (x-1)(x+2)(x+3)(x+6)
c. f(x)= (x-3)(x-2)(x+1)(x+6)
d. f(x)= (x-3)(x-2)(x-1)

72 is the answer to this problem

a is the right answer

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.