The table shows the results of rolling a number cube, with sides labeled 1 through 6, several times. What is the experimental probability of rolling a 1 or a 5?

Outcome Number of times outcome occurred
1 10
2 6
3 4
4 8
5 6
6 6

we are given a event of rolling as die several times:

Outcome:                                         [1 2 3 4 5 6]

Number of times outcome occurred: [10    6 4 8 6 6]

We have to find the experimental probability of rolling a 1 or a 5

number of times 1 or 5 came up= 10+6=16

and total number of outcomes=  10+6+4+8+6+6=  40

P( rolling a 1 or a 5)=  

number of times 1 or 5 came up/ total number of outcomes

=   16/40

= 2/5

Hence, the experimental probability of rolling a 1 or a 5 is:

   2/5

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.