Read the proof.
Given: AEEC; BDDC
Prove: △AEC ~ △BDC
Triangle A E C is show...
Mathematics, 17.12.2020 01:10, lolh1832
Read the proof.
Given: AEEC; BDDC
Prove: △AEC ~ △BDC
Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C.
Statement Reason
1. AEEC;BDDC 1. given
2. ∠AEC is a rt. ∠; ∠BDC is a rt. ∠ 2. definition of perpendicular
3. ∠AEC ≅ ∠BDC 3. all right angles are congruent
4. ? 4. reflexive property
5. △AEC ~ △BDC 5. AA similarity theorem
What is the missing statement in step 4?
∠ACE ≅ ∠BCD
∠EAB ≅ ∠DBC
∠EAC ≅ ∠EAC
∠CBD ≅ ∠DBC
Answers: 1
Mathematics, 21.06.2019 17:00, joejoefofana
Simone claims the initial value and y-intercept are the same thing on a graph. is she correct? if you know that a line has a slope of and a y-intercept of 7, what is the equation for that line in slope-intercept form?
Answers: 1
Mathematics, 21.06.2019 21:10, basketball6076
Given: lines a and b are parallel and line c is a transversal. prove: 2 is supplementary to 8 what is the missing reason in the proof? statement reason 1. a || b, is a transv 1. given 2. ∠6 ≅ ∠2 2. ? 3. m∠6 = m∠2 3. def. of congruent 4. ∠6 is supp. to ∠8 4. def. of linear pair 5. ∠2 is supp. to ∠8 5. congruent supplements theorem corresponding angles theorem alternate interior angles theorem vertical angles theorem alternate exterior angles theorem
Answers: 3
Spanish, 19.01.2020 04:31
Mathematics, 19.01.2020 04:31
Mathematics, 19.01.2020 04:31
Biology, 19.01.2020 04:31
History, 19.01.2020 04:31