Given line y-1/6x+9,find a perpendicular line to the given line passes through points (6,-3)?

y + 3 = (6)(x - 6)

Step-by-step explanation:

The proper format for this equation y-1/6x+9 is y = (-1/6)x+9.

Any line perpendicular to y = (-1/6)x+9 has the slope which is the negative reciprocal of that of y = (-1/6)x+9, or the negative reciprocal of -1/6.  That is +6.  

Thus, the desired line, which passes through (6, -3), is found using the point-slope formula for the equation of a straight line:

y + 3 = (6)(x - 6)

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5