in a random sample 70 people it was found that 44 of them were fans for the New York Yankees what is the margin of error for a true proportion of all individuals who are fans of the New York Yankees

The general formula for the margin of error would be:

z * √[p (1-p) ÷ n]

where:

z = values for selected confidence level

p = sample proportion

n = sample size

Since the confidence level is not given, we can only solve for the

√[p (1-p) ÷ n]  part.

p = 44/70

n = 70

√[44/70 (1 - (44/70) ÷ 70]

√[0.6286 (0.3714)] ÷ 70

√0.2335 ÷ 70

√0.0033357 = 0.05775 or 0.058 Choice B.

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step-by-step explanation:

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